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A population of frogs consists of 81 percent with speckles (recessive) and 19 % without speckles (dominant). What are the frequencies of p and q alleles if this population is in Hardy-Weinberg equilibrium? Show work.

Answer :

The correct answer would be the frequency of the recessive allele in a population  

The Hardy-Weinberg equations are  

p + q = 1

p² + q² + 2pq = 1

p stands for the frequency of a dominant allele in a population.

q stands for the frequency of a recessive allele in a population.

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