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HELP PLEASE ILL GIBE BRANLIEST TO WHOEVER CAN SOLVE THIS WITH NO LINKS!!!!!! If 4.00 moles of a gas at a pressure of 5.40 atmospheres have a
volume of 120 liters, what is the temperature of this gas? (R = .0821
L. atm L. atm
K mol K.
komol)
F. 190 K
G. 234 K
H. 1973 K
J. 2280 K
C.9.A-R/C.2.G-P

HELP PLEASE ILL GIBE BRANLIEST TO WHOEVER CAN SOLVE THIS WITH NO LINKS!!!!!! If 4.00 moles of a gas at a pressure of 5.40 atmospheres have a volume of 120 liter class=

Answer :

Answer:

Option H

Explanation:

We can get the temperature of the gas by applying ideal gas law,

PV = nRT

Here, P = Pressure of the gas

V = Volume of the gas

n = Number of moles

R = Gas constant

T = Temperature

By substituting the values in the given equation,

5.40 × 120 = 4 × 0.0821 × T

648 = 0.3284T

T = [tex]\frac{648}{0.3284}[/tex]

T = 1973.20

   ≈ 1973 K

Therefore, temperature of the gas is 1973 °K

Option H will be the answer.

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