Answer:
Step-by-step explanation:
x^2 + 3x - 9 =0
By comparing with the equation ax^2+bx+c = 0,
we get,
a = 1, b=3, c = -9
we know the formula for x is,
x = (-b±√(b^2 - 4ac))/2a
x = (-3±√45)/2
x = (-3±3√5)/2
x = (-3+3√5)/2, (-3-3√5)/2
Answer:
2 solutions. x = -3/2 + 3/2 * sqrt(5) and x = -3/2 + -3/2 * sqrt(5)
Step-by-step explanation:
x^2 + 3x −9 = 0
For this equation: a=1, b=3, c=-9
1x^2 + 3x+ −9 = 0
Step 1: Use quadratic formula with a=1, b=3, c=-9.
x = (-b ± [tex]\sqrt{b^2 - 4ac}[/tex])/2a
x = (-3 ± [tex]\sqrt{3^2 - 4(1)(-9)}[/tex])/2a
x = (-3 ± [tex]\sqrt{45}[/tex])/2
x = -3/2 + 3/2 * sqrt(5) or x = -3/2 + -3/2 * sqrt(5)
