Answer :

kjlong1313

Answer:

x= 11.205 and -1.205

Explanation:

3(x^2-10x-25)=33

3x^2-30x-75=33

3x^2-30x-108=0

Using the quadratic formula: x=[-b+/- sqrt(b^2 - 4ac)]/2a

x = {30 +/- sqrt(90-4(3)(-108)}/2(3)

solve with both addition and subtraction options to get

x= 11.205 and -1.205

slm45

Answer:

So in the end we'll have three sets of Xs.

(x+2), (x-5), and (x+7).

x+2=0 x-5=0 x+7=0

x=-2 x=5 x=-7

Explanation:

[tex](3x {}^{2} - 30x + 42) \div 3 = 0 \\ x {}^{2} - 10x + 14 = 0 \\ x {}^{2} - 5x + 2x + 14 = 0 \\ x(x - 5) + 2(x + 7) = 0 [/tex]

[tex]3(x - 5) {}^{2} = 33 \\ 3(x - 5)(x - 5) = 33 \\ 3(x {}^{2} - 10x + 25) = 33| \\ 3x {}^{2} - 30x + 75 - 33 = 0 \\ 3x {}^{2} - 30x + 42 = 0 [/tex]

Hope this helps.....

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