Answer :
Answer:
[tex]\frac{1+b}{2} - 3(a-1) = \frac{b- 6a+7}{2}[/tex]
Step-by-step explanation:
Given
[tex]\frac{1+b}{2} - 3(a-1)[/tex]
Required
An equivalent expression
[tex]\frac{1+b}{2} - 3(a-1)[/tex]
Take LCM
[tex]\frac{1+b}{2} - 3(a-1) = \frac{1+b- 2*3(a-1)}{2}[/tex]
[tex]\frac{1+b}{2} - 3(a-1) = \frac{1+b- 6(a-1)}{2}[/tex]
Open bracket
[tex]\frac{1+b}{2} - 3(a-1) = \frac{1+b- 6a+6}{2}[/tex]
Collect like terms
[tex]\frac{1+b}{2} - 3(a-1) = \frac{b- 6a+6+1}{2}[/tex]
[tex]\frac{1+b}{2} - 3(a-1) = \frac{b- 6a+7}{2}[/tex]
Hence, an equivalent expression is:
[tex]\frac{b- 6a+7}{2}[/tex]