Answer :
Answer:
12.5% percentage of the atoms in a sample of plutonium-238 will remain radioactive after 263.1 yr
87.5%
1. The percentage of atoms that will remain radioactive is 12.5%
2. The percentage of atoms that would have changed to a stable isotope is 87.5%
How to determine the number of half-lives
- Half-life (t½) = 87.7 years
- Time (t) = 263.1 years
- Number of half-lives (n) =?
n= t / t½
n = 263.1 / 87.7
n = 3
1. How to determine the amount remaining
- Original amount (N₀) = 100%
- Number of half-lives (n) = 3
- Amount remaining (N) =?
N = N₀ / 2ⁿ
N = 100 / 2³
N = 100 / 8
N = 12.5%
2. How to determine the amount stabled
- Original amount = 100%
- Amount remaining = 12.5%
- Amount stabled =?
Amount stabled = 100 – 12.5
Amount stabled = 87.5%
Learn more about half life:
https://brainly.com/question/26374513
#SPJ2