Answer:
A
Step-by-step explanation:
sin: [tex]\frac{opposite}{hypotenuse}[/tex]
sin: [tex]\frac{CB}{AC}[/tex] = [tex]\frac{5}{11}[/tex]
For triangle ABC, sin(A) = 5/11
"If the angle measure less than 90° then it is an acute angle."
For a right triangle,
sin(theta) = opposite side/hypotenuse
where theta is an acute angle.
For given example,
we have been given a right triangle ΔABC
Since ∠B = 90°, ∠A and ∠C must be an acute angles.
⇒ sin(A) = BC/AC
⇒ sin(A) = 5/11
and sin (C) = AB/AC
⇒ sin(C) = (4√6)/11
Therefore, sin(A) = 5/11
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