Answer :
Answer:
[tex]3 \: s[/tex]
Step-by-step explanation:
[tex]y = - 16 {x}^{2} + 32x + 48 \\ 0 = \frac{ - 16 {x}^{2} + 32x + 48 }{ - 16} \\0 = {x}^{2} - 2x - 3 \\ 0= {x}^{2} - 3x + x - 3 \\ 0= x(x - 3) + 1(x - 3) \\0 = (x + 1)(x - 3) \\ \\ x + 1 = 0 \\ x = - 1 \\ x - 3 = 0 \\ x = 3[/tex]
Hope this helps you.
Can I have the brainliest please?
Answer:
Step-by-step explanation:
You can't do anything but substitute for h and t in this question.
t = x
y = h
h = -16t^2 + 32t + 48
This is not a calculus course I don't think, so this is your answer.