At the peak of a roller coaster ride, the rider's watch flew off his wrist. The height h in feet of the watch, t seconds after he lost it, is given by y= -16x^2 + 32x + 48. How many seconds did it hit the ground?​

Answer :

Hi1315

Answer:

[tex]3 \: s[/tex]

Step-by-step explanation:

[tex]y = - 16 {x}^{2} + 32x + 48 \\ 0 = \frac{ - 16 {x}^{2} + 32x + 48 }{ - 16} \\0 = {x}^{2} - 2x - 3 \\ 0= {x}^{2} - 3x + x - 3 \\ 0= x(x - 3) + 1(x - 3) \\0 = (x + 1)(x - 3) \\ \\ x + 1 = 0 \\ x = - 1 \\ x - 3 = 0 \\ x = 3[/tex]

Hope this helps you.

Can I have the brainliest please?

jcherry99

Answer:

Step-by-step explanation:

You can't do anything but substitute for h and t in this question.

t = x

y = h

h = -16t^2 + 32t + 48

This is not a calculus course I don't think, so this is your answer.

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