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A 0.40kg object is attached to a spring constant 160N/m so that the object is allowed to move on a horizontal frictionless surface. The object is released from rest when the sprin g is compressed 0.15m find:
a) the force on the object and b) its acceleration at this instant.

Answer :

do u know the formula
F=kx
here  F=force exerted on object by spring=?
         k=spring constant=160N
x=displacement of spring=0.15m
now tell me the result u got

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