Answer :

Willchemistry
1 mole --------- 22.4 L at ( STP )
0.875 moles ----- ?

0.875 x 22.4 / 1 => 19.6 L

hope this helps!
transitionstate

Answer:

               Volume =  19.6 L

Solution:

                     As we know that one mole of any Ideal gas at standard temperature and pressure occupies exactly 22.4 dm³ volume.

Using this reference, we can calculate the volume occupied by Krypton (Ideal situation) as,

                     1 mole of Kr occupies  =  22.4 L of Volume

So,

                  0.875 moles of Kr will occupy  = X L of Volume

Solving for X,

                       X =  (0.875 mol × 22.4 L) ÷ 1 mol

                      X =  19.6 L

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