Answer :
9514 1404 393
Answer:
9676 years
Step-by-step explanation:
Apparently, you have ...
0.38 = e^(-0.0001t)
ln(0.38) = -0.0001t . . . . . . . take the natural log; next, multiply by -10,000
t = -10000ln(0.38) ≈ 9676 . . . . years
9514 1404 393
Answer:
9676 years
Step-by-step explanation:
Apparently, you have ...
0.38 = e^(-0.0001t)
ln(0.38) = -0.0001t . . . . . . . take the natural log; next, multiply by -10,000
t = -10000ln(0.38) ≈ 9676 . . . . years