Answer :
[tex][ H_3O^+] = 10 ^{-pH} [/tex]
[tex][H_3O^+] = 10 ^{-8.7} [/tex]
[tex][H_3O^+] = 1.995*10 ^{-9} M[/tex]
hope this helps!
[tex][H_3O^+] = 10 ^{-8.7} [/tex]
[tex][H_3O^+] = 1.995*10 ^{-9} M[/tex]
hope this helps!
The h3o+ of a solution with pH = 8.7 is 1.995×10∧-9
Relation between pH and concentration of H+
The pH is equal to logarithm of reciprocal of concentration of H+.
pH = ㏒1/[H+]
pH = - ㏒[H+]
- pH = ㏒[H+]
[H+] = 10∧-pH
If pH = 8.7 of h3o+
Then, h3o+ dissociates as.
H3O+ ⇄ H+ + H2O
Then,
[H+] = 10∧-pH
[H+] = 10∧-8.7
[H+] = 1.995×10∧-9
To learn more about pH here.
https://brainly.com/question/15289741
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