Answer:
[tex]\huge\boxed{\sf Solution\ Set = \{0,6\}}[/tex]
Step-by-step explanation:
[tex]\displaystyle \frac{2x}{x+4} = \frac{x}{x-1} \\\\Cross \ Multiplying \\\\x(x+4) = 2x(x-1)\\\\x^2 + 4x = 2x^2 -2x\\\\2x^2 -x^2 = 4x + 2x\\\\x^2 = 6x \\\\x^2 -6x = 0\\\\Either,\\\\x = 0 \ \ \ \ OR \ \ \ \ x-6 = 0\\\\x = 0 \ \ \ \ OR \ \ \ \ x = 6[/tex]
Hence,
Solution Set = {0,6}
[tex]\rule[225]{225}{2}[/tex]
Hope this helped!
~AH1807
