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The terminal ray of an angle passes through the point (16,–12). What is the value of sine for this angle?​

Answer :

Answer:

-3/5

Step-by-step explanation:

Given :-

  • The terminal ray of an angle passes through the point (16,–12).

And we need to find the value of sine for this angle. Therefore we can say that , Base = 16 units and Perpendicular = 12 units . So Using Pyhthagoras Theorem , we can find hypontenuse.

Using Pythagoras Theorem :-

[tex]:\implies[/tex] = +

[tex]:\implies[/tex] = 16² + 12²

[tex]:\implies[/tex] = 256 + 144

[tex]:\implies[/tex] = 400

[tex]:\implies[/tex] h = 20 u

Therefore the sine will be :-

[tex]:\implies[/tex] sinθ = p/h

[tex]:\implies[/tex] sinθ = 12/20

[tex]:\implies[/tex] sinθ = 3/5

  • And it is in third quadrant so , sine will be negative .

[tex]:\implies[/tex] sinθ = -3/5

Therefore the value of sine is -3/5.

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