Answer :
11 !
Explained below
let the number of bulbs-n
power=potential difference* current
n * 100 = 220* 5
n = 220*5/100 = 11
11 bulbs can safely used with 5 Ampere fuse.
Explained below
let the number of bulbs-n
power=potential difference* current
n * 100 = 220* 5
n = 220*5/100 = 11
11 bulbs can safely used with 5 Ampere fuse.