Answer :

sreedevi102

Answer

[tex]3^{7y} * 81^{8y} * 3^9 * 27^{-9y} = 3^{7y} * (3^4)^{8y} * 3^9 *(3^3)^{-9y}[/tex]          

                                [tex]=3^{7y} * (3)^{32y} * 3^9 *(3)^{-27y}\\\\=3^{7y +32y +9 -27y}\\\\=3^{12y+9}[/tex]

Tip :    

[tex]\frac{1}{27^{9y}} = 27^{-9y} = (3^3)^{-9y} = 3^{-27y}[/tex]                          

S1NGH

Answer:

[tex]3^{12y+9}[/tex]

Step-by-step explanation:

→ Convert all integers to base 3

[tex]3^{7y} *3^{4*8y}*3^{9} /3^{3*9y}[/tex]

→ Simplify

[tex]3^{7y}*3^{32y} *3^{9} /3^{27y}[/tex]

→ Collect all the like terms

[tex]3^{12y+9}[/tex]

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