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Set up for both orders of integration for the integral below where R is the arc of a circle radius 2 in the first quadrant. Show that both orders produce the same result by integrating each of them.

∫ ∫(2x) dA
R

Answer :

Answer:

[tex]2 \times \frac{5}{5} [/tex]

Set up for both orders of integration for the integral below where R is the arc of a circle radius 2 in the first quadrant. Show that both orders produce the same result by integrating each of them.

∫ ∫(2x) dA

R

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