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Ari has a total of 22 coins consisting of pennies and nickels. The total value of the coins is $0.54.
How many of each type of coin does Ari have?

Answer :

Noah11012
Let n = the number of nickels that Ari has.
Let p = the number of pennies that Ari has.

The total number of coins she has is 22.

n + p = 22

We have our first equation... But we another one to solve this.

Each penny is going to be $0.01 and a nickel is work $0.05.

And the total is $0.54

Our second equation. 0.05n + 0.01p = 0.54

n + p = 22
0.05n + 0.01p = 0.54

Multiply the top by -0.05

-0.05n - 0.05p = -1.1
0.05n + 0.01p = 0.54

The n terms cancel out.

-0.04p = -0.56

p = 14

Substitute p back into the top equation.

n + 14 = 22

n = 8

So, Ari has 8 nickels and 14 pennies.
0362821

Answer:

Let n = the number of nickels that Ari has.

Let p = the number of pennies that Ari has.

The total number of coins she has is 22.

n + p = 22

We have our first equation... But we another one to solve this.

Each penny is going to be $0.01 and a nickel is work $0.05.

And the total is $0.54

Our second equation. 0.05n + 0.01p = 0.54

n + p = 22

0.05n + 0.01p = 0.54

Multiply the top by -0.05

-0.05n - 0.05p = -1.1

0.05n + 0.01p = 0.54

The n terms cancel out.

-0.04p = -0.56

p = 14

Step-by-step explanation:

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