Answer :
Answer:
The answer is "[tex]0.157\ L[/tex]"
Explanation:
Please find the complete question in the attached file.
[tex]M_1=13.5\ M\\\\V_1=58.0\ ml\\\\M_2=5.00\ M\\\\[/tex]
Using formula:
[tex]M_1V_1=M_2V_2\\\\V_2 = \frac{(M_1V_1)}{M_2}\\\\[/tex]
[tex]= \frac{(13.5 \times 58.0)}{5.0}\\\\= 156.6 \ ml\\\\[/tex]
[tex]= \frac{156.6}{1000}\ L\\\\ =0.157\ L\\\\[/tex]
