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A defibrillator is used during a heart attack to restore the heart to its normal beating pattern. A defibrillator passes 18 A of current: through the torso of person in 2.0 ms- (a) How much charge moves during this time

Answer :

Answer:

q = 0.036 C

Explanation:

Given that,

Current passes through a defibrillator, I = 18 A

Time, t = 2 ms

We need to find the charge moved during this time. We know that,

Electric current = charge/time

[tex]q=It[/tex]

Put all the values,

[tex]q=18\times 0.002\\\\q=0.036\ C[/tex]

So, 0.036 C of charge moves during this time.

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