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According to Ohm's law, determine the
experimental current for these values in Table A.
voltage = 5 V, resistance = 20 N:
A
voltage = 20 V, resistance = 20 N:
A
voltage = 50 V, resistance = 20 N:
A

Answer :

Solution :

We know, by to Ohm's law :

[tex]Current = \dfrac{Voltage}{Resistance}[/tex]

For, case 1 :

[tex]I = \dfrac{5}{20}\ A = 0.25 \ A[/tex]

For, case 2 :

[tex]I = \dfrac{20}{20} \ A\\\\I = 1 \ A[/tex]

For, case 3 :

[tex]I = \dfrac{50}{20}\ A\\\\I = 2.5 \ A[/tex]

Therefore, this is the required solution.

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