dheepty0103
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Between 06 00 and 10 00,the same day ,the volume of water in a reservoir decreased from 24 000L to 18 000L.What was the average rate of decrease in volume of water, giving your answer in L/h?

Answer :

Answer:

-1.5 L/h

Step-by-step explanation:

The volume of water in a reservoir decreased from 24.000L to 18.000L between 06.00 and 10.00.

We need to find the average rate of decrease in volume of water. It can be solved as follows :

[tex]Rate=\dfrac{18-24}{10-6}\\\\=-1.5\ L/h[/tex]

The negative sign shows the decrease in volume. Hence, the rate of decrease in volume of water is 1.5 L/h.

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