Answer :
This question is incomplete, the complete question is;
Solve the homogeneous linear system corresponding to the given coefficient matrix. (If there is no solution, enter NO SOLUTION. If the system has an infinite number of solutions, set x4 = t and x2 = s and solve for x1 and x3 in terms of t and s.)
[1 0 0 1]
[0 0 1 0]
[0 0 0 0]
(x1, x2, x3, x4) =________
Answer:
the solution for the given system is; ( x₁, x₂, x₃, x₄ ) = ( -t, s, 0, t )
Step-by-step explanation:
Given the data in the question;
coefficient matrix
[tex]\left[\begin{array}{cccc} 1&0&0&1 \\ 0&0&1&0 \\ 0&0&0&0 \end{array}\right][/tex]
Now, from linear system;
[tex]\left[\begin{array}{cccc} 1&0&0&1 \\ 0&0&1&0 \\ 0&0&0&0 \end{array}\right] \left[\begin{array}{ccc}x_1\\x_2\\x_3\\x_4\end{array}\right] = \left[\begin{array}{ccc}0\\0\\0\\0\end{array}\right][/tex]
So, with the matrix, the associated equation is;
x₁ + x₄ = 0, x₃ = 0
Number of variables is 4 and ranked of the matrix is 2,
Hence, there are infinite solutions,
There are also two free variables;
from the question,
Let x₄ = t and x₂ = s be the free variables
so
x₁ + x₄ = 0
x₁ + t = 0
x₁ = -t
Therefore, the solution for the given system is;
( x₁, x₂, x₃, x₄ ) = ( -t, s, 0, t )