A two-slit interference experiment in which the slits are 0.200 mm apart and the screen is 1.00 m from the slits. The m = 1 bright fringe in the figure is 9.49 mm from the central bright fringe. Find the wavelength of the ligh

Answer :

Answer:

λ = 1.90 10⁻⁶ m

Explanation:

The interference pattern for the two-slit case is

          d sin θ = m λ

let's use trigonometry

         tan θ = y / L

interference experiments angles are small

        tan θ = sin θ /cos θ = sin θ

        sin θ = y / L

we substitute

       d y / L = m λ

       λ = [tex]\frac{ d \ y}{m \ L}[/tex]

we calculate

       λ = 0.2000 10⁻³ 9.49 10⁻³ / (1  1.00)

       λ = 1.898 10⁻⁶ m

       λ = 1.90 10⁻⁶ m

The wavelength of the light after calculation is find out to be λ = 1.90 *10⁻⁶ m

What is wavelength?

 

The distance between two successive troughs or crests is known as the wavelength. The peak of the wave is the highest point, while the trough is the lowest.The wavelength is also defined as the distance between two locations in a wave that have the same oscillation phase.

The interference pattern for the two-slit case is

d sin θ = m λ

let's use trigonometry

[tex]tan\theta=\dfrac{y}{L}[/tex]

interference experiments angles are small

[tex]sin\theta=\dfrac{y}{L}[/tex]

we substitute

[tex]\dfrac{dy}{L}=m\lambda[/tex]    

[tex]\lambda=\dfrac{dy}{mL}[/tex]

we calculate

[tex]\lambda=\dfrac{0.2\times 10^{-3}\times 9.49\times 10^{-3}}{1\times 1}[/tex]  

[tex]\lambda=1.90\times 10^{-6}\ m[/tex]    

Hence the wavelength of the light after calculation is find out to be λ = 1.90 *10⁻⁶ m

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