Given:
Angle of depression from observation deck to a ship = 67°
Height of observation deck = 1014 feet.
To find:
The horizontal distance from the base of the skyscraper out to the ship.
Solution:
Let x be the horizontal distance from the base of the skyscraper out to the ship.
Using the given information draw a diagram as shown below.
In a right angle triangle,
[tex]\tan\theta=\dfrac{Perpendicular}{Base}[/tex]
For triangle ABC,
[tex]\tan A=\dfrac{BC}{AB}[/tex]
[tex]\tan (67^\circ)=\dfrac{1014}{x}[/tex]
[tex]x=\dfrac{1014}{\tan (67^\circ)}[/tex]
On further simplification, we get
[tex]x=\dfrac{1014}{2.35585}[/tex]
[tex]x=430.41789[/tex]
[tex]x\approx 430.4[/tex]
Therefore, the horizontal distance from the base of the skyscraper out to the ship is 430.4 feet.
Applying the Trigonometry ratio, TOA, the horizontal distance from the base of the skyscraper out to the ship is: 430.4 ft.
Recall:
The situation described is shown in an image attached below, where:
To find BA, apply TOA, which is:
tan ∅ = Opp/Adjacent
tan 67 = 1014/BA
[tex]BA = \frac{1014}{tan(67)} \\\\\mathbf{BA = 430.4 $ ft}[/tex]
Therefore, applying the Trigonometry ratio, TOA, the horizontal distance from the base of the skyscraper out to the ship is: 430.4 ft.
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