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A parabola has a vertex at (–5, 0) and passes through the point (–3, 1). Which of the following is the equation of this parabola in the form y=a(x-h)^2+k?

A parabola has a vertex at (–5, 0) and passes through the point (–3, 1). Which of the following is the equation of this parabola in the form y=a(x-h)^2+k? class=

Answer :

Answer:

y = 1/4(x + 5)^2

Step-by-step explanation:

Using the given equation form;

(h,k) represents the vertex of the parablola

To get the value of a, we use the given point

So we have;

1 = a(-3 + 5)^2 + 0

1 = a(2)^2

4a = 1

a = 1/4

so we have the equation as;

y = 1/4(x+5)^2 + 0

y = 1/4(x + 5)^2

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