If G(X) = 3x+1, then G-1(1) is

Answer:
0
Step-by-step explanation:
To find the inverse, or [tex]G^{-1}[/tex] , we must switch G(x) and x, and then make G(x) [tex]G^{-1} (x)[/tex] as we are finding the inverse, and G(x) represents the starting equation.
[tex]x = 3G^{-1} (x)+1\\x -1 = 3G^{-1} (x)\\\\\frac{x-1}{3} = G^{-1} (x)\\[/tex]
The steps used here are that we firt subtracted 1 from both sides, and then divided 3 from both sides.
To find [tex]G^{-1} (1)[/tex], we simply plug 1 into x in the inverse function, so our answer is [tex]\frac{1-1}{3} =0[/tex]