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Train A and train B leave a central station at the same time. They travel the same speed, but in opposite directions, with train A heading towards station A, and train B heading towards station B. Train A reaches station A after 212212 h. Train B reaches station B after 4 h. Station A and B are 585 mi apart.

What is the rate of the trains?

Answer :

lublana

Answer:

90 mph

Step-by-step explanation:

Let speed of  both train=x mph

Time taken by train A to reach station A=[tex]2\frac{1}{2}[/tex] hr=\frac{5]{2} h[/tex]

Time taken by train B to reach station B=4 h

Distance between two trains=585 miles

We know that

Distance=[tex] speed\times time[/tex]

Distance covered by train A=[tex]\frac{5}{2} x[/tex]

Distance covered by train B=[tex]4x[/tex]

When two trains travel in opposite direction then total distance

[tex]\frac{5}{2}x+4x=585[/tex]

[tex]\frac{5x+8x}{2}=585[/tex]

[tex]\frac{13}{2}x=585[/tex]

[tex]x=585\times \frac{2}{13}=90 mph[/tex]

Hence, the rate of both trains=90 mph

Brookehead99

Answer:

90 mph

Step-by-step explanation:

i took the test. the guy above me is correct.

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