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A biologist is researching a newly-discovered species of bacteria. At time t = 0 hours, he puts one hundred bacteria into what he has determined to be a favorable growth medium. Six hours later, he measures 450 bacteria. Assuming exponential growth, what is the growth constant "k" for the bacteria? (Round k to two decimal places.) find the
number of bacteria after 13 hours

Answer :

Answer:

k=.25068

Step-by-step explanation:

450 = 100 [tex]e^{6k}[/tex]

4.5 =   [tex]e^{6k}[/tex]

ln(4.5) = 6k

k= ln(4.5)/6

k=.25068

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