Answer :
Answer:
[tex] - \frac{1}{2} ( - 3y + 10) \\ \\ = \frac{3}{2} y - \frac{10}{2} \\ \\ = { \boxed{ \boxed{ \frac{3}{2} y - 5}}}[/tex]
Answer:
[tex] - \frac{1}{2} ( - 3y + 10) \\ \\ = \frac{3}{2} y - \frac{10}{2} \\ \\ = { \boxed{ \boxed{ \frac{3}{2} y - 5}}}[/tex]