chandraghimire320
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5.40 g of copper oxide was obtained by treating the 4.32 g of copper with nitric acid and subsequent ignition. Similarly 2.3 g of copper oxide on reduction gave 1.84 g of copper in another experiment. Show that these data illustrate the law of constant composition.​

Answer :

Here we have to show the ratio of reactants and products are same

Case-1

  • Copper oxide used=5.40g
  • Copper produced=4.32g

ratio:-

[tex]\\ \sf\longmapsto \dfrac{5.40}{4.32}=1.25\approx 1[/tex]

Case:-2

  • Copper oxide used=2.3g
  • Copper produced=1.8g

ratio:-

[tex]\\ \sf\longmapsto \dfrac{2.3}{1.8}[/tex]

[tex]\\ \sf\longmapsto 1.27\approx 1[/tex]

Hence verified

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