Answer :
Answer:
- 12 and 13
Step-by-step explanation:
Let the integers be a and b, then we have:
- [tex]a<\sqrt{160} <b[/tex]
If we square all terms we get:
- [tex]a^2<160<b^2[/tex]
It is now easier to find the squares:
- [tex]a^2 = 144\\b^2=169[/tex]
Then the integers are:
- [tex]a= \sqrt{144} =12\\b=\sqrt{169} =13[/tex]