Answered

Find an equation of the line that is parallel to the graph of 2x+3y=5 and contains the point (3, −1).

Answer :

mhanifa

Answer:

  • 2x + 3y = 3

Step-by-step explanation:

Parallel lines have same slopes.

Given line:

  • 2x + 3y = 5 ⇒
  • 3y = -2x + 5 ⇒
  • y = -2/3x + 5/3

Parallel line is:

  • y = -2/3x + b

It passes through the point (3, -1), so the y-intercept is:

  • -1 = -2/3*3 + b
  • -1 = -2 + b
  • b = -1 + 2
  • b = 1

The line is:

  • y = -2/3x + 1 ⇒
  • 3y = -2x + 3 ⇒
  • 2x + 3y = 3

Other Questions