[tex]\frac{x}{2}[/tex] is equivalent to the product of [tex]\sqrt{\frac{3x}{2} } .\sqrt{\frac{x}{6} }[/tex] .
What is the law for square root?
As for square roots, a number r is a square root of a number x if r^2 = x.
According to the question.
We have a expression in the form of square root.
[tex]\sqrt{\frac{3x}{2} } .\sqrt{\frac{x}{6} }[/tex]
Therefore, the product of [tex]\sqrt{\frac{3x}{2} }[/tex] and [tex]\sqrt{\frac{x}{6} }[/tex] is given by
[tex]\sqrt{\frac{3x}{2} } \sqrt{\frac{x}{6} }[/tex]
=[tex]\sqrt{\frac{(3x)(x)}{(6)(2)} }[/tex]
=[tex]\sqrt{\frac{x^{2} }{4} }[/tex]
=[tex]\frac{x}{2}[/tex]
Hence,[tex]\frac{x}{2}[/tex] is equivalent to the product of [tex]\sqrt{\frac{3x}{2} } .\sqrt{\frac{x}{6} }[/tex]
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