In the reaction MgCl2 + 2KOH Mg(OH)2 + 2KCl, if 3 moles MgCl2 are added to 4 moles KOH, what determines how much Mg(OH)2 is made?
A. The amount of MgCl2 + KOH
B. The amount of KCl
C. The amount of MgCl2
D. The amount of KOH
The correct option is C. The amount of MgCl2. we know this because no matter how much you increase KOH, if you dont increase Mgcl2, the amount of Mg(OH)2 remains the same. Hope this works for you
