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An object with an initial velocity of 2 m/s moves in a straight line under a constant acceleration.
Three seconds later, its velocity is 16 m/s.
(a) How far did the object travel during this time?
(b) What was the acceleration of the object?

Answer :

amam4

Answer:

(a) distance =27m

(b)acceleration =14/3ms-2

Explanation:

s=(u+v)t/2

= (2+16)3/2

=27m

v=u+at

16=2+a*3

a= 14/3ms-2

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