Vesper
Vesper
Today at 12:58 PM
Physics
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physics {deceleration}
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Аноним
Аноним
Today at 1:03 PM
Using kinematic equation, v^2 - u^2 = 2as. 5^2 - 3^2 = 2a x 16. a = 0.5m/s^2. So particle will deaccelerate at 0.5m/s^2. ( v = final velocity, u= initial velocity, a= acceleration, s= displacement.)
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