Answer :
The amount of work done by the gas in the given expansion is 1800 J.
The given parameters;
- initial volume of the ideal gas, V₁ = 0.6 m³
- final volume of the ideal gas, V₂ = 2.4 m³
- constant pressure of the gas, P = 1000 Pa
The amount of work done by the gas in the given expansion is calculated as follows;
W = PΔV
where;
- ΔV is the change in volume of the gas
Substitute the given parameters and solve for the work done;
W = 1000(2.4 - 0.6
W = 1800 J
Thus, the amount of work done by the gas in the given expansion is 1800 J.
Learn more here:https://brainly.com/question/14978695