A car is parked on a 20 degree hill. It has a mass of 1550 kg. What is the frictional force on the car?

Answer:
Explanation:
The friction force must balance (acting up slope) the weight component of the car (acting down slope)
Ff = mgsinθ
Ff = 1550(9.8)sin20
Ff = 5,195.28597...
Ff = 5200 N