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What’s the kinetic energy of the object? Use .
Erica is competing in the shot put event at a track meet. She hurls a shot with a mass of 4 kilograms at a speed of 9 meters/second. The shot’s kinetic energy is joules.

Answer :

Answer:

We have: K.E. = mv² / 2

here, m = 4 Kg

v = 9 m/s

Substitute their values into the expression:

K.E. = (4)(9)² / 2

K.E. = (4)(81) / 2

K.E. = 324 / 2

K.E. = 162 Joules

Explanation:

In short answer: it would be K.E.=162 Joules

The kinetic energy of an object varies directly with the square of the speed of an object. The required kinetic energy of the shot is f 162 J.

What is Kinetic Energy?

The energy possessed by an object by its motion is known as the object's kinetic energy. It depends on the speed and mass of the given object.

Given data -

The mass of shot put is, m = 4 kg.

The speed of shot put is, v = 9 m/s.

The mathematical expression for the kinetic energy of the shot put is,

[tex]KE = \dfrac{1}{2} m v^{2}[/tex]

Solving as.

[tex]KE = \dfrac{1}{2} \times 4 \times 9^{2}\\\\KE = 162 \;\rm J[/tex]

Thus, we can conclude that the required kinetic energy of the shot is of 162 J.

Learn more about the kinetic energy here:

https://brainly.com/question/999862

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