Answer :
Answer:
We have: K.E. = mv² / 2
here, m = 4 Kg
v = 9 m/s
Substitute their values into the expression:
K.E. = (4)(9)² / 2
K.E. = (4)(81) / 2
K.E. = 324 / 2
K.E. = 162 Joules
Explanation:
In short answer: it would be K.E.=162 Joules
The kinetic energy of an object varies directly with the square of the speed of an object. The required kinetic energy of the shot is f 162 J.
What is Kinetic Energy?
The energy possessed by an object by its motion is known as the object's kinetic energy. It depends on the speed and mass of the given object.
Given data -
The mass of shot put is, m = 4 kg.
The speed of shot put is, v = 9 m/s.
The mathematical expression for the kinetic energy of the shot put is,
[tex]KE = \dfrac{1}{2} m v^{2}[/tex]
Solving as.
[tex]KE = \dfrac{1}{2} \times 4 \times 9^{2}\\\\KE = 162 \;\rm J[/tex]
Thus, we can conclude that the required kinetic energy of the shot is of 162 J.
Learn more about the kinetic energy here:
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