Answer :
(2x+1)^2
= (2x + 1)(2x + 1)
= (2x)(2x) + (2x)(1) + (1)(2x) + (1)(1)
= 4x^2 + 2x + 2x + 1
= 4x^2 + 4x + 1
= (2x + 1)(2x + 1)
= (2x)(2x) + (2x)(1) + (1)(2x) + (1)(1)
= 4x^2 + 2x + 2x + 1
= 4x^2 + 4x + 1