Answer :
For the answer to the question above , the coefficient of kinetic friction(Ff) = 2.4N because:
μ= .30
Fg= 8 N
m= Fg/g -> m= 8N / 9.81m/s^2= 80kg
Fn = Fg
Ff=μ*Fn -> .30*8N = 2.4N
I hope my answer helped you. have a nice day!
μ= .30
Fg= 8 N
m= Fg/g -> m= 8N / 9.81m/s^2= 80kg
Fn = Fg
Ff=μ*Fn -> .30*8N = 2.4N
I hope my answer helped you. have a nice day!
Answer:
(1) 2.4 n
Explanation:
The force of kinetic friction between the block and the floor is given by:
[tex]F=\mu N[/tex]
where
[tex]\mu[/tex] is the coefficient of kinetic friction
N is the normal reaction of the floor against the block
For a horizontal surface (as in this case), the normal reaction is equal to the weight of the block, so [tex]N=8.0 N[/tex]. For wood-wood contact, the coefficient of kinetic friction is approximately [tex]\mu=0.3[/tex]. Therefore, the force of kinetic friction between the block and the floor is:
[tex]F=(0.3)(8.0 N)=2.4 N[/tex]