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Use technology to find the P-value for the hypothesis test described below.
The claim is that for a smartphone carrier's data speeds at airports, the mean is p = 19.00 Mbps. The sample size is n = 21 and the test statistic is t= 1.401
P-value = (Round to three decimal places as needed)

Answer :

Using the t-distribution, it is found that the p-value is of 0.177.

At the null hypothesis, it is tested that for a smartphone carrier's data speeds at airports, the mean is 19 Mbps, that is:

[tex]H_0: \mu = 19[/tex]

At the alternative hypothesis, it is tested if the mean is different than 19 Mbps, that is:

[tex]H_1: \mu \neq 19[/tex]

  • We are testing if the mean is different from a value, hence it is a two-tailed test.
  • The test statistic is t = 1.401.
  • Sample size of n = 21, hence there are 21 - 1 = 20 df.

Inputting this information into a calculator, the p-value is of 0.177.

A similar problem is given at https://brainly.com/question/13873630

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