Answer :
The number of time it take the twirler’s baton to complete one spin is 0.56 seconds
Given the following data:
- Diameter = 0.76 meter
- Centripetal acceleration = 47. 8 [tex]m/s^2[/tex]
Radius = [tex]\frac{0.76}{2}[/tex] = 0.38 m.
To determine the number of time it take the twirler’s baton to complete one spin:
Mathematically, the centripetal acceleration for the twirler’s baton is given by this formula:
[tex]A = \frac{4\pi^2 r}{t^2}[/tex]
Where:
- r is the radius.
- t is the time.
Making t the subject of formula, we have:
[tex]t =\sqrt{\frac{4\pi^2 r}{A}}[/tex]
Substituting the parameters into the formula, we have;
[tex]t =\sqrt{\frac{4(3.142)^2 \times 0.38}{47.8}}\\\\t =\sqrt{\frac{39.489 \times 0.38}{47.8}}\\\\t =\sqrt{\frac{15.0058}{47.8}}[/tex]
Time, t = 0.56 seconds
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