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The driver (Thor, of course) of a 1000 kg car puts on the brakes. The friction in the brakes
causes the car to stop in a distance of 10 m. If the car was originally traveling 25 m/s, calculate
the magnitude of the work done by friction in stopping the car.

Answer :

Eduard22sly

The magnitude of the work done by friction in stopping the car 312500 J

Determination of the acceleration of the car

  • Initial velocity (u) = 25 m/s
  • Final velocity (v) = 0 m/
  • Distance (s) = 10 m
  • Acceleration (a) =?

v² = u² + 2as

0² = 25² + (2 × a × 10)

0 = 625 + 20a

Collect like terms

0 – 625 = 20a

–625 = 20a

Divide both side by 20

a = –625 / 20

a = –31.25 m/s²

NOTE: The negative sign indicates that the car is coming to rest (i.e decelerating)

Determination of the force

  • Mass (m) = 1000
  • Acceleration (a) = 31.25 m/s²
  • Force (F) =?

F = ma

F = 1000 × 31.25

F = 31250 N

How to determine the Workdone

  • Force (F) = 31250 N
  • Distance (d) = 10 m
  • Workdone (Wd) =?

Wd = F × d

Wd = 31250 × 10

Wd = 312500 J

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