Considering the fact that the function has a value of 0 at the origin and no vertical asymptotes, the graph represents:
B: y = Arcsin(x).
What are the vertical asymptotes of a function f(x)?
The vertical asymptotes are the values of x which are outside the domain, which in a fraction are the zeroes of the denominator.
In this problem, the function has no vertical asymptotes, hence it does not involve secant(1/cos) or tangent(sin/cos).
Since f(0) = 0, it is y = Arcsin(x), as sin(0) = 0, hence option B is correct.
More can be learned about inverse trigonometric functions at https://brainly.com/question/1143565
