Step-by-step explanation:
[tex] log_{b}(6) = 1.79[/tex]
Change of Base Formula,
[tex] \frac{ log(6) }{ log(b) } = 1.79[/tex]
[tex] \frac{ log_{}(b) }{ log(6) } = \frac{1}{1.79} [/tex]
[tex] log_{6}(b) = \frac{1}{1.79} [/tex]
or
0.55865.... round if neededd