shanay2
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You can model an arch at your school using the equation. y = -3/4(x + 4) (x – 4), where "x" and "y" are measured in feet. The x-axis represents ground.

Find the width of an arch at ground level.

Answer :

the width of thr arch at ground level is 12

The width of the arch at ground level is 8 units if the equation. y = -3/4(x + 4) (x – 4), where "x" and "y" are measured in feet.

What is a parabola?

It is defined as the graph of a quadratic function that has something bowl-shaped.

As we know that, the arch meet the ground when y = 0

[tex]\rm y = -\dfrac{3}{4}(x + 4) (x- 4)[/tex]

Plug y = 0

(x + 4)(x - 4) = 0

x = 4 or x = 0 = -4

The points are (4, 0) and (-4, 0)

The distance between the above two points:

w = 8 units

Thus, the width of the arch at ground level is 8 units if the equation. y = -3/4(x + 4) (x – 4), where "x" and "y" are measured in feet.

Learn more about the parabola here:

brainly.com/question/8708520

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