Answer :
Answer:
- 16.875 feet²
Solution:
We are given that :
- Length of rectangular dog cage = [tex]\sf 4\dfrac{1}{2} [/tex] feet.
- Width of rectangular dog cage = [tex]\sf 3\dfrac{3}{4} [/tex] feet.
Area of the cage:
- ➙ Length × width
Therefore,
[tex] \implies\quad \tt {A = Length \times Width}[/tex]
[tex] \implies\quad \tt {A = 4\dfrac{1}{2}\times 3\dfrac{3}{4} }[/tex]
[tex] \implies\quad \tt { A =\dfrac{(4\times 2)+1}{2}\times \dfrac{(3\times 4)+3}{4}}[/tex]
[tex] \implies\quad \tt {A =\dfrac{8+1}{2}\times \dfrac{12+3}{4} }[/tex]
[tex] \implies\quad \tt { A =\dfrac{9}{2}\times \dfrac{15}{4}}[/tex]
[tex] \implies\quad \tt { A = \dfrac{135}{8}}[/tex]
[tex] \implies\quad \underline{\underline{\pmb{\tt {A = 16.875}} }}[/tex]
Step-by-step explanation:
Given :-
- Length :- 4½ feet
- Width :- 3¾ feet
To find :-
- Area of rectangular dog cage
Solution :-
Area of rectangular dog cage :- l×w
putting the values,
[tex]3 \frac{3}{4} \times 4 \frac{1}{2} [/tex]
[tex] \frac{15}{4} \times \frac{9}{2} [/tex]
Area = 135/8 feet²
Area = 16.875 ft²