Answer :

linandrew41

The equation of the circle is [tex](x-h)^{2} +(y-k)^{2} =r^{2}[/tex]

  • (h,k) center of the circle --> (-6, 6)
  • r is the radius --> [tex]\sqrt{(-5--6)^2 + (9-6)^2} = \sqrt{1 +9} =\sqrt{10}[/tex]

Thus the equation of the circle is:

  [tex](x+6)^{2} +(y-6)^2=10[/tex]

Hope that helps!

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